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Chapter 25 Energy from chemical responses Q1. Sodium nitrate dissolves readily in water according to the equation NaNO3(s) ? NaNO3(aq); ?H = +21.0 kJ gram moleecule1 aDetermine the postal code change when 1.0 g of solid NaNO3 is turn in water. bWould you expect the temperature to rise or come out to pass when sodium nitrate dissolves in water? inform your answer. A1. an(NaNO3) = =0.0117 molee 1 mole NaNO3 absorbs 21 kJ push 0.0117 mole absorbs 0.0117 × 21 kJ = 0.25 kJ bThe temperature will fall. Since the reaction is endothermic the enthaply of reactants is higher than the enthalpy of products, i.e. the reaction absorbs energy. Q2. Calculate the energy released when the following quantities of ethane gas hit the roof mark according to the equation: 2ethane(g) + 7O2(g) ? 4CO2(g) + 6H2O(l); ?H = 3120 kJ mol1 a3.00 mol b100 g c10.0 L at SLC A2. aFrom the equation, lend oneself stoichiometry to occur energy released. 2 mol ethane releases 31 20 kJ of energy 3.00 mol C2H6 releases ´ 3.00 kJ So energy = 4680 kJ = 4.68 ´ 103 kJ b tone 1Calculate the count of ethane, using n = . n(C2H6)= = 3.326 mol spirit 2Use stoichiometry to find energy released. 2 mol C2H6 releases 3120 kJ of energy 3.326 mol C2H6 releases 3120 ´ kJ So energy released= 5189 kJ = 5.

19 ´ 103 kJ cStep 1Calculate the amount of ethane, using n = at SLC. n(C2H6)= = 0.4082 mol Step 2Use stoichiometry to find energy released. 2 mol C2H6 releases 3120 kJ of energy 0.4082 mol C2H6 releases 3120 ´ kJ So energy released= 636.7 kJ = 637 kJ Q3. What vol ume of ethane, measured at STP, must be bur! n down according to the equation in brain 2 in order to yield 100 kJ of warming energy? A3. Step 1Use stoichiometry to find the amount of C2H6. 3120 kJ is released by 2 mol 100 kJ is released by 2 ´ mol So n(C2H6)= 2 ´ = 0.641 mol Step 2Calculate the volume of C2H6 at STP, using n = . V(C2H6)= n ´ Vm = 0.641 mol ´ 22.4 L...If you want to soak up a full essay, order it on our website: BestEssayCheap.com

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